A+B+C + D + E+F+G + H + I
Here it says that all the alphabets are from distinguished numbers from 1-9Which means A-I represent numbers 1-9 and sum of A+B+C+D+E+F+G+H+I=sum of first 9 natural numbers which is 45Also the sum of (A+B+C)+(C+D+E)+(E+F+G)+(G+H+I|)=13+13+13+13=13*4=52So if we replace A+B+C+D+E+F+G+I by 45 in the above equation we get C+E+G=52-45=7C+E+G=7AlsoC+D+E=13Now C,E,G can be from 1,4,2If we check for E=4 we find that we can get all the numbers distinguished from each other for each alphabet.Try taking value of E 1,2 and you will get smiler alphabet for 2 or more digits.Hence E=4
Here it says that all the alphabets are from distinguished numbers from 1-9
ReplyDeleteWhich means A-I represent numbers 1-9 and sum of A+B+C+D+E+F+G+H+I=sum of first 9 natural numbers which is 45
Also the sum of (A+B+C)+(C+D+E)+(E+F+G)+(G+H+I|)=13+13+13+13=13*4=52
So if we replace A+B+C+D+E+F+G+I by 45 in the above equation
we get C+E+G=52-45=7
C+E+G=7
Also
C+D+E=13
Now C,E,G can be from 1,4,2
If we check for E=4 we find that we can get all the numbers distinguished from each other for each alphabet.
Try taking value of E 1,2 and you will get smiler alphabet for 2 or more digits.
Hence E=4